Fiber a = 25 μm, n1 = 1,48; Δ = 0,01; λ = 0,84 μm;
calculate V; M; Pclad/P;
if Δ = 0,003, calculate M and Pclad/P;
V= (2πan_1)/λ √2Δ
V= (2π.25.〖10〗^(-6))/(0,84.〖10〗^(-6) ) √2.0,01
V= 26.445 m/s
M = V2 / 2 = (26,445)2 / 2 = 349,67
Pclad/P = 4/3 (M)-0.5
= 4/3 (349.67)-0.5
= 0.07
if Δ = 0,003 then,
V= (2πan_1)/λ √2Δ
V= (2π.25.〖10〗^(-6))/(0,84.〖10〗^(-6) ) √2.0,003
V= 14,48 m/s
M = V2 / 2 = (14,48)2 / 2 = 104,8352
Pclad/P = 4/3 (M)-0.5
= 4/3 (104,8352)-0.5
= 0,13